Capacitor Bank Calculation For APFC Panel

Capacitor Bank Calculation For APFC Panel

Welcome to this introductory part on capacitor bank calculation for an APFC  panel. When I first started working on the calculation of capacitor bank  I have struggled for many hours to figure out what was going on in this Capacitor bank calculation. Therefore, I have decided to write this tutorial for the ones who are new to these topic.
In this tutorial, we will discuss the calculation for capacitor bank in a simple way.

There are two methods for calculation of capacitor bank –

  1. Simple Table Method for Capacitor bank calculation
  2. Classical Capacitor bank Calculation Method

Let us take a example of 3Phase induction motor

1.Simple Table Method for capacitor bank calculation – 

Motor Input = 5kW

From Table, Multiplier to improve Power factor from 0.7 to 0.96 is 0.692

Required Capacitor kVAR to improve P.F from 0.7 to 0.96

Required Capacitor kVAR = kW x Table  Multiplier of 0.7 and 0.96

= 5kW x 0.692

= 3.46 kVAR

And Rating of Capacitors connected in each Phase

3.46/3 = 1.15 kVAR

2. Classical capacitor bank Calculation Method

Motor input = P = 5 kW, Voltage- 400V

Original Power factor= Cosθ1 = 0.7

Final Power factor = Cosθ2 = 0.96

θ1 = Cos-1  (0.7) = 0.7953; Tan θ= Tan (0.7953) = 1.0200

θ= Cos-1 (0.96) = 0.2837; Tan θ= Tan (0.2837) = 0.2915

Required Capacitor kVAR to improve Power factor from 0.7 to 0.96

Required Capacitor kVAR = P (Tan θ– Tan θ2)

= 5kW (1.0200 – 0.2915)

= 3.46 kVAR

And Rating of Capacitors connected in each Phase

3.46/3 = 1.15 kVAR

 

These are the main Formulas to Convert Capacitor kVAR into Farads and Vice Versa

C = kVAR / (2 π f V2) in microfarad

C = 3.46/ (2 π* 50*4002) in microfarad

C= 6.88* 10^-8 microfarad

By |2018-11-12T17:57:52+00:00November 12th, 2018|Categories: Electrical Engineering Projects, Engineering Projects, Project DataBase|Tags: |0 Comments

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